stpcpy — copy a string returning a pointer to its end
#include <string.h>
char
*stpcpy( |
char *restrict dest, |
const char *restrict src) ; |
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Note | ||||
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The stpcpy
() function copies
the string pointed to by src
(including the terminating
null byte ('\0')) to the array pointed to by dest
. The strings may not
overlap, and the destination string dest
must be large enough to
receive the copy.
stpcpy
() returns a pointer
to the end of the
string dest
(that is,
the address of the terminating null byte) rather than the
beginning.
For an explanation of the terms used in this section, see attributes(7).
Interface | Attribute | Value |
stpcpy () |
Thread safety | MT-Safe |
This function was added to POSIX.1-2008. Before that, it was not part of the C or POSIX.1 standards, nor customary on UNIX systems. It first appeared at least as early as 1986, in the Lattice C AmigaDOS compiler, then in the GNU fileutils and GNU textutils in 1989, and in the GNU C library by 1992. It is also present on the BSDs.
For example, this program uses stpcpy
() to concatenate “foo”
and “bar” to produce “foobar”, which it then
prints.
#define _GNU_SOURCE #include <string.h> #include <stdio.h> int main(void) { char buffer[20]; char *to = buffer; to = stpcpy(to, "foo"); to = stpcpy(to, "bar"); printf("%s\n", buffer); }